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Platinum Ionization Energy

The Platinum Ionization Energy is the energy required to remove from atom one mole of electrons with subsequent production of positively charged ion of Platinum.
Pt -> Pt+ + e-
This process can be repeated many times, but the energy cost is increased dramatically. The general equation for the Platinum is:
PtN+ -> Pt(N+1)+ + e-

Ionization Energy

Pt -> Pt1+ = 870 kJ/mol = 208.13 Kcal/mol
Pt1+ -> Pt2+ = 1791 kJ/mol = 428.47 Kcal/mol
Pt2+ -> Pt3+ = 2800 kJ/mol = 669.86 Kcal/mol
Pt3+ -> Pt4+ = 3900 kJ/mol = 933.01 Kcal/mol
Pt4+ -> Pt5+ = 5300 kJ/mol = 1267.94 Kcal/mol
Pt5+ -> Pt6+ = 7200 kJ/mol = 1722.49 Kcal/mol
Pt6+ -> Pt7+ = 8900 kJ/mol = 2129.19 Kcal/mol
Pt7+ -> Pt8+ = 10500 kJ/mol = 2511.96 Kcal/mol
Pt8+ -> Pt9+ = 12300 kJ/mol = 2942.58 Kcal/mol
Pt9+ -> Pt10+ = 14100 kJ/mol = 3373.21 Kcal/mol

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