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Potassium Tetrachlor-platinite, K2PtCl4

Potassium Tetrachlor-platinite, K2PtCl4, is obtained technically by passing sulphur dioxide into a solution of chlor-platinic acid, maintained at about 100° C., until a sample yields no precipitate with ammonium chloride. This indicates that reduction is complete. A hot solution of twice the calculated quantity of potassium chloride is added, and the chlor-platinite allowed to crystallise out. It is washed with alcohol and dried in the absence of light.

Although a solution of pure potassium hexachlor-platinate, K2PtCl6, is not reduced by boiling with potassium oxalate, reduction readily takes place if a trace of iridium in solution is added. In the presence of much iridium the reaction may even become violent.

The density of potassium tetrachlor-platinite is 3.3056 at 20.3° C., and 3.2909 at 21° C., whilst its heat of formation is:

[Pt] + (Cl2) + 2[KCl] = [K2PtCl4] + 45.17 Cals.

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